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From a circular disc of radius R and ma...

From a circular disc of radius R and mass 9 M , a small disc of mass M and radius `( R)/(3)` is removed concentrically. What will be the moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through the centre?

Text Solution

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The correct Answer is:
`(40MR^(2))/(9)`
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Knowledge Check

  • From a circular disc of radius R and mass 9m a small disc of radius (R/3) is removed from the disc the moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is (

    A
    `4MR^2`
    B
    `40/9MR^2`
    C
    `10MR^2`
    D
    `37/9MR^2`

  • The moment of inertia of a uniform circular disc is maximum about an axis perpendicular to the disc and Passing through

    A
    A
    B
    B
    C
    C
    D
    D

  • From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre?

    A
    `(13 MR^(2))/(32)`
    B
    `(11 MR^(2))/(32)`
    C
    `(9 MR^(2))/(32)`
    D
    `(15MR^(2))/(32)`

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