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Find (i) the moment of inertia of a rod ...

Find (i) the moment of inertia of a rod of mass 100 g and length 100 cm about and axis passing through its centre and perpendicular to its length and (ii) the radius of gyration.

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Mass of rod , M = 100 g = 0.1 kg , length, L = 100 cm = 1m.
(i) Moment of inertia about the said axis is ,
`I =(1)/(12)ML^(2)=(1)/(12)xx0.1xx1^(2)`
(ii) If k is the radius of gyration then
` I = Mk^(2)`
or,`k = sqrt((I)/(M))=sqrt(((1)/(120))/(0.1))=sqrt((1)/(2))=0.29 `m
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