Assuming that the earth moves around the sun in a circular orbit, find the orbital speed (in `km*h^(-1)`) and the orbital angular velocity of the earth. The radius of the earth's orbit `=1.5xx10^8km`.

Explanation

Time period of the earth (T) =365 d =`365xx24h`
Radius of the orbit ( r ) `=1.5xx10^8km`
`therefore` Orbital speed (v) `=(2pir)/T=(2xxpixx1.5xx10^8)/(365xx24)`
`=1.076xx10^5km*h^(-1)`
Orbital angular velocity `(omega) =v/r =(2pi)/T=(2xxpi)/(365xx24)`
`=7.17xx10^(-4)rad *h^(-1)`.