Home
Class 11
PHYSICS
Two small but heavy spheres , each of ma...

Two small but heavy spheres , each of mass M are on a horizontal plane separated by a distance r. Find the gravitational potential at the mid-point of the line joining the centres of the two spheres.

Text Solution

Verified by Experts

Gravitational potential at the mid-point of the line joining the two centres,
`V=(-GM)/(r//2)+(-GM)/(r//2)=-(2GM)/r -(2GM)/r=-(4GM)/r`.
Promotional Banner

Topper's Solved these Questions

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise SECTION RELATED QUESTIONS|18 Videos
  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|41 Videos
  • NEWTON'S LAWS OF MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|24 Videos
  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

Similar Questions

Explore conceptually related problems

Two small but heavy spheres of mass M each are kept at a distance r on a horizontal plane. The magnitude of the gravitational potential at the mid-point of the line joining the centres of the two spheres will be

Two heavy spheres each of mass 100 kg and radius 0.10 m are placed 1.0 m apart on a horizontal table. What is the gravitational force and potential at the mid-point of the line joining the centres of the spheres ? Is an object placed at that point in equilibrium ? if so, is the equilibrium stable or unstable ?

Two parallel coaxial circular coils of equal radius R and equal number of turns N, carry N carry equal currents I in the same direction and are separated by a distance 2R. Find the magnitude and direction of the magnetic field produced at the mid point of the joining their centres.

A mass M at rest is broken into two pieces having masses m and (M-m). The two masses are then separated by a distance r. The gravitational force between them will be the maximum when the ratio of the masses [m: (M-m)] of the two parts is

Find the distance of the point (1, 2) from the mid-point of the line segment joining the points (6, 8) and (2, 4).

Two short bar magnets of length 1 cm each have magnetic moments 1.20A.m^(2) and 1.00A.m^(2) respectively . They are placed on a horizontal table parallel to each other with their N poles pointing towards the south . They have a common magnetic equator and are separated by a distance of 20.0 cm . The value of the resultant horizontal magnetic induction at the mid - point O of line joining their centres is close to (horizontal component of earth's magnetic induction is 3.6xx10^(-5) "Wb " . m^(-2) )

Show that the gravitational potential at a point, distance r from the mass M is given by V =-(GM/r)

CHHAYA PUBLICATION-NEWTONIAN GRAVITATION AND PLANETARY MOTION-CBSE SCANNER
  1. Two small but heavy spheres , each of mass M are on a horizontal plane...

    Text Solution

    |

  2. What is the reason for absence of atmosphere in some planets?

    Text Solution

    |

  3. State Kepler's laws on planetary motion. Explain the way the three law...

    Text Solution

    |

  4. Discuss the variation of g with depth. What happens to g at the centre...

    Text Solution

    |

  5. Define orbital speed. Derive the expression for it.

    Text Solution

    |

  6. Define escape velocity. Derive the expression for it.

    Text Solution

    |

  7. A body weight 63N on the surface of the earth. What is the gravitation...

    Text Solution

    |

  8. Deduce Kepler's second laws of planetary motion for a planet.

    Text Solution

    |

  9. Obtain an expression showing variation of acceleration due to gravity ...

    Text Solution

    |

  10. Why does a satellite not need any fuel to circle around the earth? Is ...

    Text Solution

    |

  11. What would be the weight of a person, if he goes to a height equal to ...

    Text Solution

    |

  12. Derive an expression for the escape velocity of an object from the sur...

    Text Solution

    |

  13. A saturn year is 29.5 times the earth year. How far is the saturn from...

    Text Solution

    |

  14. Derive an expression for acceleration due to gravity at a depth d from...

    Text Solution

    |

  15. A remote-sensing satellite of earth revolves in a circular orbit at a ...

    Text Solution

    |

  16. Define escape velocity. Derive an expression for escape velocity.

    Text Solution

    |

  17. According to Newton's law of gravitation , everybody in this universe ...

    Text Solution

    |

  18. According to Newton's law of gravitation , everybody in this universe ...

    Text Solution

    |

  19. According to Newton's law of gravitation , everybody in this universe ...

    Text Solution

    |

  20. A body weight 63 N on the surface of the earth. What is the gravitatio...

    Text Solution

    |