An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, `g=980 cm*s^(-2)`.

Explanation

Radius of the earth, R=6400 km `=64xx10^7cm`
Distance of the artificial satellite from the centre of the earth
r=6400 +300=6700 km `=67xx10^7cm`.
Orbital speed of the artificial satellite ,
`v=Rsqrt(g/r)=64xx10^7sqrt((980)/(67xx10^7))`
`=7.74xx10^5cm *s^(-1)=7.74 km*s^(-1)`
Time period of revolution,
`T=(2pir)/(v)=(2xxpixx67xx10^7)/(7.74xx10^5)=5439 s`
=1h 30 min 39 s.