An artificial satellite is orbiting around the earth at a height of 3400 km above the earth's surface in a circular orbit. Find the orbital speed of the satellite. The radius of the earth =6400 km and `g=980 cm*s^(-2)`.

Explanation

Radius of the earth `R=6400 km 64xx10^7 cm`
Distance of the artificial satellite from the centre of the earth,
r=6400 +3400 =9800 km `=98xx10^7 cm`
Hence , the orbital speed of the satellite ,
`v=Rsqrt(g/r)=64xx10^7sqrt((980)/(98xx10^7))`
`= 6.4xx10^5 cm *s^(-1)=6.4 km *s^(-1)`.