A satellite at a height of 700 km is revolving around the earth in a circular orbit. Find the velocity of the satellite with respect to the earth's surface. (Radius of the earth R=6300 km, `g=9.8 m*s^(-2))`.

Explanation

Radius of the earth R =6300 km `=63xx10^5m`.
Distance of the satellite from the centre of the earth,
`r=6300+700=7000 km =7xx10^6 m`
hence velocity of the artificial satellite ,
`v=Rsqrt(g/r)=63xx10^5sqrt((9.8)/(7xx10^6))74.543xx10^2m*s^(-1)`
`7.454 km *s^(-1)`.