Two particles of equal mass revolve in a circular path of radius R due to their mutual force of attraction. Find the velocity of each particle.

Explanation

At any time, during the revolution , the two particles stay at the ends of any diameter of the circular path Mutual force of gravitation acts along the diameter . Considering the motion of any one of the particles,
`(Gmxxm)/((2R)^2)=(mv^2)/R or, v^2=(Gm)/(4R) or, v=sqrt((Gm)/(4R))`.