If the mass of the earth is 6xx10^(27)g ...

If the mass of the earth is `6xx10^(27)`g and its radius 6400 km, what will be the acceleration due to gravity at a height 64 km above the earth's surface ? Given that `G=6.67xx10^(-8)` CGS unit.

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The correct Answer is:

`957.5 cm*s^(-2)`

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CHHAYA PUBLICATION-NEWTONIAN GRAVITATION AND PLANETARY MOTION-PROBLEM SET -I

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