The radius of a planet is double than that of the earth but their average densities are the same. If the escape velocities of the planet and the earth are `v_p and v_e` respectively, then prove that `v_p=2v_e`.

The mass of a planet is 4 times the mass of the earth and its radius is 2 times the radius of the earth. The acceleration due to gravity on that planet is

The value of the escape velocity from the earth is v_e . If the radius of a planet is 4 times that of the earth and its density is 9 times the density of the earth, then the value of the escape velocity from that planet will be

The orbital velocity of a satellite in a circular orbit close to the earth is v_0 , If the escape velocity of an object projected from the earth be v_e , then the ratio of these two velocities is.

The orbital velocity f a satellite in a circular orbit close to the earth is v_0 . If the escape velocity of an object projected from the earth be v_e , then the ratio of these two velocities is

Gravitational acceleration on the surface of a planet is (sqrt(6)//11) g, where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 2/3 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 km*s^(-1) , the escape speed on the surface of the planet in km*s^(-1) will be

The acceleration due to gravity on the surface of the earth is 9.8 m*s^(-2) . The size of a planet is the same as that of the earth, but its density is twice the density of the earth. The value of the acceleration due to gravity on that planet is