A body of mass m is raised to a height h from a point on the surface of the earth of the earth where the acceleration due to gravity is g. Prove that the loss of weight due to variation of g is `(2mgh)/R` , where R is the radius of the earth.

What is the value of the acceleration due to gravity on the surface of the earth ?

Keeping the mass fixed , if the radius of the earth is halved, the acceleration due to gravity at any place will be

Where does the body weight more at the surface of the earth or in a mine ?

An object of mass m is raised up to a small height h above the earth's surface. If the acceleration due to gravity on the earth's surface is g, prove that the weight of the object will decreases by (2mgh)/R with respect to that on the earth's surface . R =radius of the earth.

If the radius of the earth is R , the height above the surface of the earth where the acceleration due to gravity will be 1% of its value on the earth's surface is

At what height above the surface of the earth will the acceleration due to gravity be one-fourth of its value on the surface of the earth ?[Radius of the earth =R]

If the earth is assumed to be a sphere of radius R, the height above the surface of the earth where the value of the acceleration due to gravity will be half its value on the earth's surface is

A satellite of mass m is revolving around the earth at a height x above the surface of the earth. The radius of the earth is R. If the acceleration due to gravity is g, the orbital speed of the satellite will be

At what height above the surface of earth acceleration due to gravity will be (i) 4%