Considering the earth as a uniform sphere of radius R show that if the acceleration due to gravity at a height h from the surface of earth is equal to the acceleration due to gravity at the same depth, then `h=1/2(sqrt(5)-1)R.`

What is the value of the acceleration due to gravity on the surface of the earth ?

What is the value of the acceleration due to gravity at the centre of the earth ?

At what height above the surface of earth acceleration due to gravity will be (i) 4%

what is the value of acceleration due to gravity at the centre of the earth ?

The acceleration due to gravity at a height R ( radius of the earth ) from the earth' s surface is

Assume that the earth is a uniform sphere of radius R. If the acceleration due to gravity at a height h above the earth's surface is g_1 and at the same depth below the surface of the earth is g_2(h lt R) , then show that, g_2=g_1(1-h/R)(1+h/R)^2 .

Keeping the mass fixed , if the radius of the earth is halved, the acceleration due to gravity at any place will be

Derive an expression for acceleration due to gravity at a depth d from earth's surface . Is it increases or decreases.