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Two particle of mass m1 and m2 approach ...

Two particle of mass `m_1 and m_2` approach each other due to their mutual gravitational attraction only. Then

A

acceleration of both the particles are equal

B

acceleration of the particle of mass `m_1` is proportional to `m_1`

C

acceleration of the particle of mass `m_1` is proportional to `m_2`

D

acceleration of the particle of mass `m_1` is inversely proportional to `m_1`.

Text Solution

Verified by Experts

The correct Answer is:
C

Force ,`F=(Gm_1m_2)/(r^2)`
So, acceleration of the particle with mass `m_1` ,
`a_1=F/(m_1)=(Gm_2)/(r^2)`
i.e., `a_1 prop m_2`
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