Home
Class 11
PHYSICS
At what height from the surface of earth...

At what height from the surface of earth the gravitation potential and the value of g are `-5.4xx10^7J*kg^(-1) and 6 m*s^(-2)` respectively ? Take the radius of earth as 6400 km.

A

1600 km

B

1400 km

C

2000 km

D

2600 km

Text Solution

Verified by Experts

The correct Answer is:
D
Let, at height h from the surface of the earth the gravitation potential and the value of g are respectively equal to the given values.
`therefore V_h=-(GM)/(R+h)=-5.4xx10^7J*kg^(-1)`
`g_h=(GM)/((R+h)^2)=6 m*s^(-2)`
`therefore (V_h)/(g_h)=((R+h)^2)/(R+h)=R+h=(5.4xx10^7)/(6)=0.9xx10^7`
`therefore h=(0.9xx10^7-R)=(0.9xx10^7-6400xx10^3) =2.6xx10^6m=2600 km`
Promotional Banner

Topper's Solved these Questions

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (AIPMT)|3 Videos

  • NEWTON'S LAWS OF MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|24 Videos

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

Similar Questions

Explore conceptually related problems

At what height above the surface of the earth is the gravitational potential energy of a body equal to that on the surface of the moon ? Assume that the mass of the earth is 80 times that of the moon and the radius of the earth is 4 times that of the moon. Given ,Radius of the earth =6400 km.

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.

If g is the acceleration due to gravity on the surface of the earth , the gain in potential energy of an object of mass m raised from the earth's surface to a height equal to the radius R of the earth is

At what height above the surface of earth acceleration due to gravity will be (ii) 50% of its value on the surface of the earth. Given radius of earth =6400 km.

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .

The gravitational potential energy of a body on the surface of the earth is -6.4xx10^6 joule. Explain the statement.

The average density of the earth is 5500kg*m^(-3) the gravitational constant is 6.7xx10^(-11)N*m^2*kg^(-2) and the radius of the earth is 6400 km. Using the given values, find the magnitude of the acceleration due to gravity on the surface of the earth.