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What amount of work must be done in stre...

What amount of work must be done in stretching a wire, of length 1 m and of cross sectional area `1mm^2`, by 0.1mm? Young's modulus for the material `=2 times 10^11 N.m^-2`.

Text Solution

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We know that , work done, `W=1/2(Yal^2)/L`
Here, `Y=2times10^11N.m^-2,a=1mm^2=10^-6m^2`
`l=0.1mm=10^-4m,L=1m`
`thereforeW=1/2times(2times10^11times10^-6times(10^-4)^2)/1=10^-3J`.
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