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When the load on a wire is increased fro...

When the load on a wire is increased from 3kg to 5kg, the elongation of the wire increases from 0.6mm to 1mm.How much work is done during this extension of the wire?

Text Solution

Verified by Experts

We know that, work done, `W=1/2Fl`.
Let the work done in stretching the wire through 0.6mm be `W_1`.
Here, `F=3kgf=(3times9.8)N`
and `l=0.6 mm=6 times 10^-4 m`
`thereforeW_1=1/2times3times9.8times6times10^-4=8.82times10^-3J`
Let the work done in stretching the wire through 1mm be `W_2`.
In this case , `F=5 kgf=5 times 9.8 N`
and `l=1 mm=10^-3 m`
`thereforeW_2=1/2times5times9.8times10^-3=2.45times10^-2J`
So, during the extension of the wire from 0.6 mm to 1 mm, the net work done `=W_2-W_1=(2.45times0.882)times10^-2`
`=1.568times10^-2J`
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