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IF the work done in stretching a uniform...

IF the work done in stretching a uniform wire, of cross section `1mm^2` and length 2m, by 1mm is 0.05 joule, find the young's modulus for the material of the wire.

Text Solution

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Work done, `W=1/2(Yal^2)/L`
So, `Y=(2WL)/(al^2)`
Here, `W=0.05J,alpha=1mm^2=10^-6m^2,L=2m,`
`l=1mm=10^-3m`
`thereforeY=(2times0.05times2)/(10^-6times(10^-3)^2)=2times10^11N.m^-2`
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