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A steel is 1.5 m long at 20^(@)C. What w...

A steel is 1.5 m long at `20^(@)C`. What will be the increase in its length if it is heated up to `100^(@)C?" "alpha` for steel `=11 times 10^(-6@)C^(-1)`.

Text Solution

Verified by Experts

Here, `l_(1)=1.5m=150cm, alpha=11 times 10^(-6@)C^(-1)`,
`t_(1)=20^(@)C " and " t_(2)=100^(@)C`
Increase in length `=l_(2)-l_(1)=l_(1)alpha(t_(2)-t_(1))`
`" "=150 times 11 times 10^(-6) times (100-20)`
`" " =150 times 11 times 10^(-6) times 80`
`" " =0.132cm`.
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