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Two ends of a wire are rigidly clamped....

Two ends of a wire are rigidly clamped. If its temperature is decreased by `10^(@)C`, find the change in the tension of the wire.
Area of cross-section of the wire `=0.01cm^(2)`,
`alpha=16 times 10^(-6@)C^(-1), Y=20 times 10^(11) dyn.cm^(-2)`

Text Solution

Verified by Experts

Here `A=0.01 cm^(2), Y=20 times 10^(11)dyn.cm^(2)`,
`alpha=16 times 10^(-6@)C^(-1), t=10^(@)C`
`therefore` Change in tension
`" " Ayat=0.01 times 20 times 10^(11) times 16 times 10^(-6) times 10`
`" " =32 times 10^(5) dyn.`
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