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A 1 L flask contains some mercury. It is...

A 1 L flask contains some mercury. It is observed that the volume of air in the flask remains unchanged at all temperatures. What is the volume of mercury in the flask? Coefficient of linear expansion of the material of the flask `=9 times 10^(-6@)C^(-1)`and coefficient of real expansion of mercury `=1.8 times 10^(-4@)C^(-1)`

Text Solution

Verified by Experts

Let the volume of mercury be V and the rise in temperature be `theta^(@)C`. When the volume of air in the flask remains unaltered, expansion of mercury = volume expansion of the flask.
`therefore " " V times theta times 1.8 times 10^(-4)=1000 times theta times 3 times 9 times 10^(-6)`
or, `" " V=(27 times 10^(-3))/(1.8 times 10^(-4))=150 cm^(3).`
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