Home
Class 11
PHYSICS
A copper collar is to fit tightly about ...

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at `20^(@)C`. The inside diameter of the copper collar at that temperature is 5.98 cm.
The tensile stress in the copper collar when its temperature returns to `20^(@)C` is `(Y=11 times 10^(10)N*m^(-2))`

A

`1.34 times 10^(5)N*m^(-2)`

B

`3.68 times 10^(-12)N*m^(-2)`

C

`3.68 times 10^(8)N*m^(-2)`

D

`1.24 times 10^(-12)N*m^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER - INTEGER TYPE|4 Videos

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE - WBCHSE|3 Videos

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER - MULTIPLE CORRECT ANSWERS TYPE|7 Videos

  • EXPANSION OF GASES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|1 Videos

  • FIRST AND SECOND LAW OF THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos

Similar Questions

Explore conceptually related problems

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at 20^(@)C . The inside diameter of the copper collar at that temperature is 5.98 cm. If the breaking stress of copper is 230 N*m^(-2) at what temperature will the copper collar break as it cools?

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at 20^(@)C . The inside diameter of the copper collar at that temperature is 5.98 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the steel shaft remains at 20^(@)C ? (alpha_("cooper")=17 times 10^(-6)K^(-1))

A steel ring is heated up to 95^(@)C to fit exacty on the outer surface of an iron cylinder of diameter 10 cm at 20^(@)C. After fitting, the ring is cooled so that the system attains a temperature 20^(@)C. What is the thermal stress of the ring? [Young's modulus of steel = 21 times 10^(5)kg*cm^(-2) " and " alpha for steel =12 times 10^(-6@)C^(-1).]

A square metal plate of side 100 cm at 0^(@)C , has a circular hole of diameter 40 cm in the middle of it. At what temperature, will each side by 101 cm long? What will be the diameter of the hole at that temperature? alpha for the metal =12.5 times 10^(-6@)C^(-1)

A mercury thermometer contains 0.4cm^(3) of mercury at 0^(@)C. The diameter of the capillary tube of the thermometer is 0.2 mm. What should be the length of the scale to measure temperatures between 0^(@)C " to " 100^(@)C ? The coefficient of apparent expansion of mercury =1.7 times 10^(-4@)C^(-1).

At 30^@C , the hole in a steel plate has diameter of 0.99970 cm. A cylinder of diameter exactly 1cm at 30^@C is to be slide into the hole. To what temperature the plate must be heated? (Given : alpha_(steel)=1.1xx10^-5//^@C )

A steel is 1.5 m long at 20^(@)C . What will be the increase in its length if it is heated up to 100^(@)C?" "alpha for steel =11 times 10^(-6@)C^(-1) .

An iron sphere is to be passed through a circular brass ring. At 20^(@)C , the diameter of the sphere is 25 cm and the internal diameter of the ring is 24.9 cm. If both the sphere and the ring are heated together, at what temperature will the sphere just pass through the ring? alpha for iron =1.2 times 10^(-5@)C^(-1) and alpha for brass =2times10^(-5@)C^(-1) .