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A hydrogen cylinder can withstand an int...

A hydrogen cylinder can withstand an internal pressure of `7 times 10^6 Pa`. The pressure of hydrogen inder at `15^@C` is `1.7 times 10^6` Pa. At what minimum temperature an explosion may take place?

Text Solution

Verified by Experts

Given `p_1=1.7 times 10^6 Pa`
and `T_1=273+15=288K`
Explosion may occur at a pressure `p_2=7 times 10^6 Pa`
As volume is constant in the cylinder. From pressure law,
`p_1/T_1=p_2/T_2or,T_2=(p_2T_1)/p_1`
`thereforeT_2=(7times10^6 times 288)/(1.7 times 10^6)=1185.9K`
`=(1185.9-273)^@C=927^@C`
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