Air is enclosed in a glass container at `67^@C`. Find the temperature to which the container is to be raised at constant pressure, so that `1/3 rd` of the final volume of the air is expelled from the vessel?{Neglect the expansion of glass}?

Explanation

Let initially the volume of air =`V_1`.
In this case, temperature of air,
`T_1=273+67=340 K`.
Suppose the volume of the air becomes `V_2` at a temperature `T_2`.
`therefore` Volume of expelled air =`1/3 V_2`
`thereforeV_2=V_1+1/3V_2or,V_2=3/2V_1`
Since the pressure is constant, we can write `V_1/T_1=V_2/T_2`
`therefore V_1/340=(3/2V_1)/T_2`
or, `T_2=3/2 times 340 =510 K=(510-273)^@C=237^@C`.