Draw p-T graph for masses m and 2m of the same gas, when heated in a container of constant volume. Interpret the slopes.

Explanation

The desired graphs are shown in fig.6.17.
The equation of state for mass m of a gas of molecular weight M is
`pV=m/MRT or,p=(mR)/(MV)T`
Given V=constant, so for any fixed mass, p= constant `times` T.
Thus, the p-T graph is a straight line passing through the origin [FIg.6.17].
Also the slope `(mR)/(MV)` is higher for a higher m.
`therefore` The slope of the graph for mass 2m is more than that for mass m.
For any temperature the value of p in the first case will be half of second case. `(BC=1/2 AC)`