An ideal gas is initially at pressure p and volume V. its pressure is increased by dp, so that its volume decreases by dV, while temperatures remains constant. Here `B=-1/V(dV)/(dP)`.What will be the nature of the graph between B and p?

Explanation

In case an ideal gas `pV=RT `
If the temperature remains constant pV=constant
`therefore pdV+Vdp=0`
or, `(dV)/(dp)=-V/P`
`therefore B==1=constant`
So the graph `B-p` will be a rectangular hyperbola [Fig.6.21]