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Mass of object is 200g and its specific ...

Mass of object is 200g and its specific heat is `"0.09 cal. g"^(-1).^(@)C^(-1)`. How much that heat is required to increase its temperature from `20^(@)C` to `90^(@)C`?

Text Solution

Verified by Experts

Here, `m=200g, s="0.09 cal. G"^(-1).^(@)C^(-1)`.
`t_(1)=20^(@)C, t_(2)=90^(@)C`
`therefore " Heat required,"`
`H=ms(t_(2)-t_(1))=200xx0.09xx(90-20)`
`=200xx0.0xx70="1260 cal."`
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