It is given that the specific heat of water in `cal.g^(-1)` unit is `s=0.6t^(2)`, where t is the temperature in Celsius scale. what amount of heat is required to raise the temperature of 10g water from `0^(@)C` to `10^(@)C` ?

Explanation

Heat required to increase the temperature of water by an amount dt is ,
`dH=ms dt =mxx0.6t^(2)dt`
So, to raise the temperature of water from `0^(@)C` to `10^(@)C`, heat required,
`H=int dH=int_(0)^(10)mxx0.6t^(2)dt=mxx0.6[(t^(3))/(3)]_(0)^(10)`
`=10xx0.6xx((10)^(3))/(3)="2000 cal."`