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A solid of mass 70 g is heated and dropp...

A solid of mass 70 g is heated and dropped in a calorimeter of water equivalent 10 g conaining 116 g of water. If the fall in temperature of the solid is 15 times the rise in temperature of water, find the specific heat capacity of the solid .

Text Solution

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Let t be the rise in temperture of water and s the specific heat of the solid.
Fall in temperature of the solid = 15 t
Heat lost by the solid `=70xxsxx15t`
Heat gained by the calorimeter and water
`=10xxt+116xx1xxt=126t`
Since, heat lost = heat gained
`70xxsxx15t=126t`
`"or, "s=(126)/(70xx15)="0.12 cal.g"^(-1).^(@)C^(-1)`
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