Home
Class 11
PHYSICS
A body of mass 100 g is heated up to 122...

A body of mass 100 g is heated up to `122^(@)C` and dropped quickly in water of mass 300 g kept at `28^(@)C` in a copper calorimeter of mass 50 g. The final temperature of the mixture becomes `30^(@)C.` If the specific heat of copper is `"0.09 cal.g"^(-1).^(@)C^(-1)`, find the specific heat of the material of the body.

Text Solution

Verified by Experts

Let the specific heat of the material be s.
Heat lost by the body `=100xxsxx(122-30)`
`=100xxsxx92="9200 s cal"`
Heat gained by water `=300xx1xx(30-28)`
`=300xx2="600 cal"`
Heat gaind by the calorimeter
`=50xx0.09xx(30-28)=4.5xx2="9 cal"`
We know, heat lost = heat gained
`"or, "9200s=600+9`
`"or, "s=(609)/(9200)="0.0662 cal.g"^(-1).^(@)C^(-1)`
Promotional Banner

Topper's Solved these Questions

  • CALORIMETRY

    CHHAYA PUBLICATION|Exercise Section Related Questions|1 Videos

  • CALORIMETRY

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|15 Videos

  • CIRCULAR MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos

Similar Questions

Explore conceptually related problems

Thermal capacity of a body of mass 10 g is "8 cal ".^(@)C^(-1) . The specific heat of the material of the body is

A piece of platinum of mass 200 g, is heated for a sufficiently long time in a furnace and dropped quickly in 650 g of water at 10^(@)C , kept in a container of water equivalent 50g. Final temperature of the mixture becomes 25^(@)C . If the specific heat capacity of platinum is "0.03 cal.g"^(-1).^(@)C^(-1) , find the temperature of the furnace.

If the specific heat of copper is "0.1 cal. G"^(-1).^(@)C^(-1) , then water equivalent of a copper calorimeter of mass 0.4 kg is

'Specific heat of iron is "0.106 cal.g"^(-1).^(@)C^(-1) '- what do you mean by this statement?

Mass of a calorimeter made of copper is 80 g. If the specific heat of copper is "0.09 cal. g"^(-1).^(@)C^(-1) , determine the thermal capacity and water equivalent of the calorimeter?

Mass of a piece of cppper is 20 g. Find the rise in temperature of the piece when 100 cal of heat is supplied to it? Specific heat of copper ="0.09 cal. g"^(-1).^(@)C^(-1).

A body of mass 20 g at 100^(@)C is dropped into 200 g of water at 30^(@)C . What will be the final temperature of the mixture ? Specific heat of the material of the body ="0.1 cal. G"^(-1).^(@)C^(-1).

An alloy contains 60% copper and 40% nickel. A piece of this alloy of mass 50 g is heated to 50^(@)C and than dropped into a calorimeter of water equivalent 10 g containing 40 g of water at 20^(@)C . Calculate the final temperature of the mixture. Specific heat of copper ="0.09 cal.g"^(-1).^(@)C^(-1) , and of nickel = "0.11 cal.g"^(-1).^(@)C^(-1)

10g of water at 30^(@)C and 5g of ice at -20^(@) C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice= 0.5 cal g^(-1) (""^(0)C)^(-1) and latent heat of fusion of ice =80 cal g^(-1)

A container contains 50 gm of a liquid at 20^@C 100 gm water at 100^@C is added to it. If the final temperature of the mixture is 40^@C . Find the specific heat of liquid