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1 kg of water in a kettle of water equiv...

1 kg of water in a kettle of water equivalent 200 g can be heated from `15^(@)C` to `90^(@)C` in 15 min by the heat supplied by a kerosene stove at the rate of `6xx10^5"cal . H"^(-1)`. What percentage of the heat produced by the stove is absorbed by the kettle and water?

Text Solution

Verified by Experts

Heat produced in 60 min by the kerosene stove `=6xx10^(5)"cal"`
`therefore" Heat produced in 15 min by the stove"`
`=(6xx10^(5)xx15)/(60)=15xx10^(4)"cal"`
Heat gained by the kettle and water in 15 min
`=200xx(90-15)+1000xx(90-15)`
`=1200xx75=9000=9xx10^(4)"cal"`
`therefore" Heat absorbed "`
`=(9xx10^(4))/(15xx10^(4))xx100=60%`
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