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Mass of a body is M, its specific heat i...

Mass of a body is M, its specific heat is S and temperature is T. The body is dropped in a liquid. If the mass of the liquid is m, specific heat is s and temperature is t,then prove that the final temperature of the mixture is `theta=(MST+mst)/(MS+ms)`.
If the liquid is water then show that, `S=(m(theta-t))/(M(T-theta))`.

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