What is the amount of work done to convert 40 g of ice at `-10^(@)C` into steam at `100^(@)C`? Specific heat of ice `= 0.5 cal cdot g^(-1) cdot ^(@)C^(-1)`, latent heat of fusion of ice `=80 cal cdot g^(-1)`, latent heat of steam = `540 cal cdot g^(-1), J = 4.2 xx 10^(7) erg cdot cal^(-1)`.

Answer

`1.218 xx 10^(12) erg`