1 kg oil is taken in a copper calorimeter having mass 100 g. This oil is stirred vigorously by applying a torque of `10^(8) dyn cdot cm` with the help of a rotating paddle. The temperature of the oil rises by `5^(@)C` after 220 rotations. Determine the mechanical equivalent of heat. Specific heat of copper = `0.09 cal cdot g^(-1) cdot^(@)C^(-1)` and specific heat of oil = `0.64 cal cdot g^(-1) cdot^(@)C^(-1)`.

Answer

`4.26 xx 10^(7) erg cdot cal^(-1)`