An ideal gas is compressed from state `(P_(1), V_(1), T)` to state `(P_(2), V_(2), T)` isothermally. What is the change in the internal energy of the gas? Answer with reason.

A quantity of an ideal gas is compressed from state (p_(1), V_(1)) to another state (p_(2), V_(2)) (i) isothermally, (ii) adiabatically. In which process will the work done be greater?

2 mol of an ideal monatomic gas is carried from a state (P_(0), V_(0)) to a state (2P_(0), 2V_(0)) along a straight line path in a P - V diagram. The amount of heat absorbed by the gas in the process is given by

2 mole of an ideal monatomic gas is carried from a state (P_(o),V_(0)) to state (2P_(0),2V_(o)) along a straight line path in a P-V diagram. The amount of heat absorbed by the gas in the process is given by

(i) 1 mol of an ideal gas expands isothermally and reversible from (P_(1)V_(1)T) to (P_(2)V_(2)T) . Write down the equation showinig the amount of heat absorbed by the given ideal gas. (ii) In an isothermal expansion of an ideal gas, the pressure of the gas decreases from P_(1) to P_(2) . write down the equation of work done by the gas in this process. (iii) The temperature of 1 mol of an ideal gas is increased from T_(1) and T_(2) . write down the equations for the changes in enthalpy and internal energy.

An ideal gas undergoes four processes: isochoric, isobaric, isothermal and adiabatic. In which process is (i) the change in internal energy zero?

1 mol of an ideal gas is compressed to half of its initial volume (i) isothermally and (ii) adiabatically. Draw the p-V diagram in each case and hence state with reason, in which case the work done in less.