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Find out the temperature at which the av...

Find out the temperature at which the average kinetic energy of a gas molecule will be equal to the energy gained by an electron on acceleration across a potential difference of 1V, Given Boltzman constant=`1.38 times 10^-23 J.K^-1`, charge of an electron =`1.6 times 10^-19 C`.

Text Solution

Verified by Experts

Energy gained by the electron
`=1eV=(1.6 times10^-19C)times1V=1.6times10^19]`
Average kinetic energy of a gas molecule
`3/2kT=3/2times(1.38times10^23)timesTJ`
`therefore1.6times10^-19=3/2times(1.38times10^-23)timesT`
or,`T=2/3times(1.6times10^-19)/(1.38times10^-23)=7729K=7456^@C`
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