Home
Class 11
PHYSICS
Find out the number of molecules in a ga...

Find out the number of molecules in a gas of volume `20cm^3` at a pressure of 76 cm of mercury. And at `27^@C` Given average molecule kinetic energy at `27^@C=2 times 10^-14 erg`.

Text Solution

Verified by Experts

Pressure of the gas
`p=1/3pc^2=1/3(mN)/Vc^2`
[m=mass of a molecule,N=number of molecules]
or, `N=(3pV)/(mc^2)=(3pV)/(2times1/2mc^2)`
[average molecular kinetic energy `=1/2 mc^2=2 times 10^-14 erg`]
`=(3times(78times13.8times980)times20)/(2times(2times10^-14))`
`=1.52times10^21`
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILLS (HOTS) QUESTIONS|33 Videos
  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise EXERCISE (Multiple Choice Questions)|24 Videos
  • HYDROSTATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|1 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos

Similar Questions

Explore conceptually related problems

Determine the number of molecules is 20 cm^3 of a gas at 27^@C and 76 cmHg pressure. Average kinetic energy per molecule at 27^@C=4 times 10^-14 erg and g=980 cm.s^-2 .

Calculate the number of molecules is 1cm^3 of an ideal gas at 27^@C . Temperature and 20 mmHg pressure. The average kinetic energy of one molecule of the gas at 27^@C=4 times 10^-14 erg , density of mercury = 13.6 g.cm^-3

"The total kinetic energy of the molecules in an ideal gas with a volume V at pressure P and temperature T is equal to the total kinetic energy of the molecules present in the same volume of another ideal gas at the same pressure and at temperature 2T"-Justify the statement.

At 27^@C the average thermal energy of He atom is [K = 1.38 xx 10^-23 J]

Find out the rms speed of a gas of density 2g.L^-1 at 76 cmHg pressure. Given density of mercury= 13.6 g.cm^-3 and g=980 cm.s^-2 .

Find out the energy of 1 mol of a gas and its average molecular kinetic energy at 27^@C . Given, R=8.3 times 10^7 erg.mol^-1.K^-1 and N_A=6.02 times 10^23 mol^-1 .

The average kinetic energy of a gas molecule at 27^@C is 6.21 xx 10^-21 J . Its average kinetic energy at 227 ^@C will be--------.

Calculate the kinetic energy of per gm molecule of He gas at 27^@C .

A fixed mass of gas occupies a volume of 273 cm^3 at STP. At what pressure the above gas will occupy a volume of 300 cm^3 at 27^@C ?

A container of volume 1 L contains 2.5 times 10^23 number of nitrogen molecules. The mass of each molecule is 4.65 times 10^23 and the rms speed of the molecule is 5 times 10^4 cm.s^-1 . Determine the pressure and the total kinetic energy of the gas.