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2 mol of a monatomic gas is mixed with 1...

2 mol of a monatomic gas is mixed with 1 mol of a diatomic gas. Find out the value of `gamma` of the mixture.

Text Solution

Verified by Experts

For the monatomic gas, `gamma_1=1+2/f=1+2/3=5/3`,
where f=number of degree of freedom
For the diatmoc gas, `gamma_2=1+2/f=1+2/5=7/5`
f=3 for a monatomic gas and f=5 for a diamotic gas So, for the mixture,
`gamma=(n_1gamma_1+n_2gamma_2)/(n_1+n_2)=(2times5/2+1times7/5)/(2+1)=1.58`
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