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The mean free path for the collision of ...

The mean free path for the collision of nitrogen molecules at STP is `6.44 times 10^-6 cm`. What is the mean time interval between collisions? Given, `R=8.31 times 10^7 erg.mol^-1.K^-1`, molecular mass of nitrogen=28.

Text Solution

Verified by Experts

rms speed,
`c=sqrt(3RT)/M=sqrt((3times(8.31times10^7)times273)/28)cm.s^-1`
`therefore` Mean time interval between collisions
`=(mean fre e path)/(rms velocity)`
`=6.44times10^-6timessqrt((28)/(3times(8.31times10^7)times273))`
`=1.306times10^-10s`
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