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22g of CO2 gas at 27^@C is mixed with 16...

22g of `CO_2` gas at `27^@C` is mixed with 16 g of `O_2` gas at `37^@C`. What will be the temperature of the mixture?

Text Solution

Verified by Experts

`22g CO_2=22/44 or 1/2 mol of CO_2`,
`16g O_2=16/32 or 1/2 mol O_2`
Temperature of the mixture
`T=(n_1T_1+n_2T_2)/(n_1+n_2)=(1/2(27+273)+1/2(37+273))/(1/2+1/2)`
`=305K=32^@C`
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