Home
Class 11
PHYSICS
The pressure exerted by an ideal gas is ...

The pressure exerted by an ideal gas is p=`1/3 M/Vc^2` where the symbols have their usual meanings. Using standard gas equation, pV=nRT we find that `c^2=(3RT)/M` or `C^2 prop T`. Average kinetic energy of translation of 1 mol of gas=`1/2 Mc^2=(3RT)/2`
At what temperature when pressure remains unchanged, will the rms speed of hydrogen be double its value at STP?

A

819 K

B

`819^@C`

C

1000 K

D

`1000^@C`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER(Integer answer type)|5 Videos
  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise Examinations Archive with Solutions(WBCHSE)|19 Videos
  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER(Multiple correct answer type)|5 Videos
  • HYDROSTATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|1 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos

Similar Questions

Explore conceptually related problems

The pressure exerted by an ideal gas is p= 1/3 M/Vc^2 where the symbols have their usual meanings. Using standard gas equation, pV=nRT we find that c^2=(3RT)/M or C^2 prop T . Average kinetic energy of translation of 1 mol of gas= 1/2 Mc^2=(3RT)/2 At what temperature, when pressure remain unchanged , will the rms speed of a gas be half its value at 0^@C ?

The pressure exerted by an ideal gas is p= 1/3 M/Vc^2 where the symbols have their usual meanings. Using standard gas equation, pV=nRT we find that c^2=(3RT)/M or C^2 prop T . Average kinetic energy of translation of 1 mol of gas= 1/2 Mc^2=(3RT)/2 Average thermal energy of 1 mol of helium at 27^0 C temperature is (given constant for 1 mol= 8.31 J.mol^-1.K^-1 )

The pressure exerted by an ideal gas is p= 1/3 M/Vc^2 where the symbols have their usual meanings. Using standard gas equation, pV=nRT we find that c^2=(3RT)/M or C^2 prop T . Average kinetic energy of translation of 1 mol of gas= 1/2 Mc^2=(3RT)/2 Average thermal energy of a helium atom at room temperature (27^@C) is (given Boltzmann constant k=1.38 times 10^-23 J.K^-1 )

Find out the temperature at which the molecular rms speed of a gas would be 1/3 rd its value at 100^@C .

For the reaction SO_2(g)+1/2 O_2(g) iff SO_3(g) if K_p = K_c(RT)^x where the symbols have usual meaning then the value of x is: (assuming ideality)

The pressure and temperature of an ideal . Gas in an adiabatic process are related as P prop T^3 . What is the value of the ratio C_P //C_v of the gas?

IF c_1,c_2,c_3 ……are random speeds of gas molecules at a certain moment then average velocity c_(av)=(c_1+c_2+c_3+.......c_n)/n are root mean square speed of gas molecules c_(rms)=sqrt((c_1^2+c_2^2+c_3^2+......+c_n^2)/n)=c Further c^2 prop T or c prop sqrt T At0K, c=0 i.e.,molecular motion stops. At what temperature when pressure remains constant, will the rms speed of the gas molecules be increased by 10% of the rms speed at STP?

Prove that c_(rms)=sqrt((2E)/(M)) [E=total kinetic energy of the molecules of 1 mol of a gas, M=molar mass of the gas, c_(rms)= root mean square velocity of gas molecule].