The mean free path of oxygen molecule at NTP is `9.5 times 10^-6 cm` What will be the time between two consecutive collisions of an oxygen molecule?(`R=8.3 times 10^7 erg.mol^-1.K^-1`)

The mean free path of oxygen gas molecules at STP is 9.5 times 10^-6 cm What is the time interval between two successive collisions of a molecule? Atomic weight of oxygen=32 and R=8.3 times 10^7 erg.mol^-1.K^-1

The mean free path for the collision of nitrogen molecules at STP is 6.44 times 10^-6 cm . What is the mean time interval between collisions? Given, R=8.31 times 10^7 erg.mol^-1.K^-1 , molecular mass of nitrogen=28.

IF the rms speed of oxygen at STP is 4.6 times 10^4 cm.s^-1 What will be its density at STP?

Resistivity of copper is 1.76 times 10^-6 Omega cm. What will be the resistance between two opposite faces of a copper cube of side 1 m?

Calculate the mean free path for the collision of nitrogen molecules at 0^@C temperature at 1 standard atmosphere pressure. The mean time interval between two successive collisions = 1.9 times 10^-10 s, R=8.31 times 10^7 erg.mol^-1.K^-1 molecular mass of nitrogen =28.

What will be the volume of one mole of oxygen at 27^@C and at a pressure twice the standard atmosphere R=8.31 times 10^7 erg.mol^-1K^-1 .

Mean free path of benzene molecule is 2.2 times 10^-6 cm and number of molecules per unit volume is 2.79 times 10^19 cm^-3 . Determine the diameter of a benzene molecule.

The average kinetic energy of a hydrogen molecule at 0^@C is 5.64 times 10^-14 erg and the universal gas constant R=8.32 times 10^7 erg.mol^-1.K^-1 . Find out the value of the avogadro number.

Find out the kinetic energy of 2g of nitrogen gas at 27^@C . Given R=8.3 times 10^7 erg.mol^-1 K^-1 .

The rms speed of oxygen gas molecules at STP is 4.5 times 10^4 cm.s^-1 . Find out the same for carbon dioxide gas molecules at STP. Given the molecular weights of oxygen and carbon dioxide are 32 and 44, respectively.