The displacement of an object attached to a spring and executing SHM is given by `x=2xx10^(-2)cospitm`. In what time the object attains maximum speed first?

Explanation

`x=2xx10^(-2)cospit`
`therefore" "v=(dx)/(dt)=-(2xx10^(-2)pi)sinpit`
v is maximum when `sinpit=pm1`
or, `pit=pi/2,(3pi)/2,(5pi)/2...`
The speed becomes maximum first when `pit=pi/2`
or, `t=1/2=0.5s`