Home
Class 11
PHYSICS
The amplitude of a particle executing SH...

The amplitude of a particle executing SHM is 0.1 m. The acceleration of the particle at a distance of 0.03 m from the equilibrium position is `0.12m*s^(-2)`. What will be its velocity at a distance of 0.08 m from the position of equilibrium?

Text Solution

Verified by Experts

The correct Answer is:
`0.12m*s^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    CHHAYA PUBLICATION|Exercise PROBLEM SET - II|32 Videos
  • SIMPLE HARMONIC MOTION

    CHHAYA PUBLICATION|Exercise HOTS NUMERICAL PROBLEMS|22 Videos
  • SIMPLE HARMONIC MOTION

    CHHAYA PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS - II|7 Videos
  • ROTATION OF RIGID BODIES

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|10 Videos
  • STATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|3 Videos

Similar Questions

Explore conceptually related problems

When a particle executing SHM is at a distance of 0.03 m from the equilibrium position, its acceleration is 0.296m*s^(-2) . What is the time period of oscillation of the particle?

The time period of a particle executing S.H.M. is T sec. Find the time taken by the particle to reach maximum displacement in one side from equilibrium position.

Knowledge Check

  • The time period of a particle having SHM is 4 s then what will be the time taken to reach half of its amplitude from equilibrium position?

    A
    `1/2` sec
    B
    `1/3` sec
    C
    `3/4` sec
    D
    `1/4` sec
  • The amplitude and frequency of a particle having SHM are 0.01 m and 60 Hz. Then the maximum acceleration of the particle is

    A
    `144pi^2m//s^2`
    B
    `120pi^2m//s^2`
    C
    `80pi^2m//s^2`
    D
    `60pi^2m//s^2`
  • The maximum speed of a particle executing s.H.M. is 1 m/s and maximum acceleration is 1.57 m/s^2 . its time period is

    A
    4sec
    B
    2sec
    C
    1.57sec
    D
    1/1.57sec
  • Similar Questions

    Explore conceptually related problems

    Acceleration of a particle having SHM is 0.12 ml S^2 . When the particle is 0.03 mt away from its equilibrium position what will be its time period?

    Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

    The time period and amplitude of a particle executing SHM are 10 s and 0.12 m respectively. Find its velocity at a distance 0.04 m from its position of equilibrium.

    A particle executes SHM with an amplitude of 13 cm and its velocity at a distance of 5 cm from the equilibrium position is 36cm*s^(-1) . Determine the maximum value of the restoring force. (Mass of the particle = 2g).

    The ratio of kinetic energy and potential energy of a particle executing SHM at a distance of 2 cm from its equilibrium position is 3 : 2. What is the amplitude of vibration of the particle?