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The maximum acceleration of a particle e...

The maximum acceleration of a particle executing simple harmonic motion is `0.296m*s^(-2)` , its time period is 2s and the displacement from the equilibrium position at the beginning of its motion is 0.015m. Determine the equation of motion of the particle.

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The correct Answer is:
`x=0.03cos(pitpmpi/6)m`
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CHHAYA PUBLICATION-SIMPLE HARMONIC MOTION-PROBLEM SET - I
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  2. The maximum acceleration of a particle executing simple harmonic motio...

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  3. What is the amplitude, frequency and initial phase of the SHM represen...

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  4. Amplitude of a SHM is, A = 7 cm, its time period, T = 2s and initial p...

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  5. A particle executes SHM with an amplitude of 13 cm and its velocity at...

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  6. Equations of two SHMs are y(1)=10sin(3pit+pi/4)andy(2)=5(sin3pit+sqrt3...

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  7. When a particle executing SHM is at a distance of 0.03 m from the equi...

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  8. A particle executes SHM of period 1.2 s and amplitude 8 cm. Find the t...

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  9. Time period and amplitude of a particle executing SHM are 2 s and 5 cm...

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  10. Time period of a particle executing SHM is T = 1 second and its amplit...

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  11. The maximum velocity of a particle executing SHM is v(m)=picm*s^(-1) a...

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  12. The equation of motion of a particle executing SHM is 3(d^(2)x)/(dt^(2...

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  13. A particle executing SHM starts from one end of its path. If the time ...

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  14. A particle of mass 5g is executing SHM. The velocity of the particle w...

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  18. What is the time period of a simple pendulum of effective length 60 cm...

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