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A particle executes SHM with an amplitud...

A particle executes SHM with an amplitude of 13 cm and its velocity at a distance of 5 cm from the equilibrium position is `36cm*s^(-1)`. Determine the maximum value of the restoring force. (Mass of the particle = 2g).

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CHHAYA PUBLICATION-SIMPLE HARMONIC MOTION-PROBLEM SET - I
  1. What is the amplitude, frequency and initial phase of the SHM represen...

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  2. Amplitude of a SHM is, A = 7 cm, its time period, T = 2s and initial p...

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  3. A particle executes SHM with an amplitude of 13 cm and its velocity at...

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  4. Equations of two SHMs are y(1)=10sin(3pit+pi/4)andy(2)=5(sin3pit+sqrt3...

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  5. When a particle executing SHM is at a distance of 0.03 m from the equi...

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  6. A particle executes SHM of period 1.2 s and amplitude 8 cm. Find the t...

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  7. Time period and amplitude of a particle executing SHM are 2 s and 5 cm...

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  8. Time period of a particle executing SHM is T = 1 second and its amplit...

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  9. The maximum velocity of a particle executing SHM is v(m)=picm*s^(-1) a...

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  10. The equation of motion of a particle executing SHM is 3(d^(2)x)/(dt^(2...

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  11. A particle executing SHM starts from one end of its path. If the time ...

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  12. A particle of mass 5g is executing SHM. The velocity of the particle w...

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  13. The ratio of kinetic energy and potential energy of a particle executi...

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  14. The bob of a simple pendulum of effective length 1 m is pulled through...

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  15. The time period of a simple pendulum is 2 s. The mass of its bob is 10...

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  16. What is the time period of a simple pendulum of effective length 60 cm...

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  17. A simple pendulum completes 20 oscillations in a minute. If the diamet...

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  18. A particle executes SHM of period 8 s. After what time of its passing ...

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  19. Due to shifting from one place to another, the time period of a simple...

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  20. What will be the effective length of a seconds pendulum on the surface...

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