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Time period and amplitude of a particle ...

Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

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The correct Answer is:
`4picm*s^(-1),3pi^(2)cm*s^(-2)`
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CHHAYA PUBLICATION-SIMPLE HARMONIC MOTION-PROBLEM SET - I
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  2. A particle executes SHM of period 1.2 s and amplitude 8 cm. Find the t...

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  3. Time period and amplitude of a particle executing SHM are 2 s and 5 cm...

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  5. The maximum velocity of a particle executing SHM is v(m)=picm*s^(-1) a...

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  9. The ratio of kinetic energy and potential energy of a particle executi...

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  15. Due to shifting from one place to another, the time period of a simple...

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  20. Which of the following functions of time represent (i) simple harmonic...

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