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Time period of a particle executing SHM ...

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.

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The correct Answer is:
`0.08pim*s^(-1),0.16pi^(2)m*s^(-2)`
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CHHAYA PUBLICATION-SIMPLE HARMONIC MOTION-PROBLEM SET - I
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  2. Time period and amplitude of a particle executing SHM are 2 s and 5 cm...

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  3. Time period of a particle executing SHM is T = 1 second and its amplit...

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  8. The ratio of kinetic energy and potential energy of a particle executi...

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  9. The bob of a simple pendulum of effective length 1 m is pulled through...

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  10. The time period of a simple pendulum is 2 s. The mass of its bob is 10...

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  11. What is the time period of a simple pendulum of effective length 60 cm...

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  12. A simple pendulum completes 20 oscillations in a minute. If the diamet...

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  13. A particle executes SHM of period 8 s. After what time of its passing ...

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  14. Due to shifting from one place to another, the time period of a simple...

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  15. What will be the effective length of a seconds pendulum on the surface...

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  16. If a simple pendulum of length 100 cm is used as a seconds pendulum, t...

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  17. The effective length of a simple pendulum is 1 m. The pendulum complet...

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  18. The time period of vibration of a massless elastic spring, with mass M...

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  19. Which of the following functions of time represent (i) simple harmonic...

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  20. Two particles execute SHM of same amplitude along the same straight li...

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