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The maximum velocity of a particle execu...

The maximum velocity of a particle executing SHM is `v_(m)=picm*s^(-1)` and the maximum acceleration is `a_(m)=pi^(2)cm*s^(-2)`. Determine the time period and the amplitude of motion of the particle.

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The correct Answer is:
2 s, 1 cm
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CHHAYA PUBLICATION-SIMPLE HARMONIC MOTION-PROBLEM SET - I
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  14. Due to shifting from one place to another, the time period of a simple...

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