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Show that the equation x=acos^(2)omegat ...

Show that the equation `x=acos^(2)omegat` represents a simple harmonic motion. Find the (i) amplitude, (ii) time period and (iii) position of equilibrium of the particle.

Text Solution

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`x=acos^(2)omegat=1/2a*2cos^(2)omegat=1/2a(cos2omegat+1)`
= `a/2+a/2cos2omegat`
The term `a/2cos2omegat` indicates simple harmonic motion.
(i) Amplitude = `1/2a`
(ii) Here, `omega.=2omega`
So, time period, `T=(2pi)/(omega.)=(2pi)/(2omega)=pi/omega`
(iii) Foe the term `a/2cos2omegat` simple harmonic motion,
acceleration = `-omega.^(2)x.=-4omega^(2)x." "[becauseomega.=2omega]`
At equilibrium position, acceleration = 0
`therefore" "0=-4omega^(2)x.or,x.=0`
As, `x=a/2+a/2cos2omegat=a/2+x.`
so, equlibrium position is,
`x=a/2+0or,x=a/2`
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