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A pendulum is hung from the roof of a su...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is `20m//s^(2)` at a distance of 5 m from the mean position. The time period of oscillation is

A

2s

B

`pis`

C

`2pis`

D

1s

Text Solution

Verified by Experts

The correct Answer is:
B

`veca=-omega^(2)vecx`
`|a|=omega^(2)xor,20=omega^(2)xx5or,omega^(2)=4or,omega=2`
`therefore" "T=(2pi)/omega=(2pi)/2=pis`
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